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Cement +Fine aggregate+ Course aggregate=Sum of components
1 : 2 : 4 = 7
Second we find the quantity of material by this formula.
Quantity of material = Ratio of material ÷ Sum of ratio × dry material of concrete
Now, we try to analyze the 100 Cft cement concrete quantity according to the ratio of (1:2:4) in F.P.S . System.
Solution:
Quantity of wet material = 100 Cft
Quantity of dry material = 100 × 1.54 = 154 Cft
Ratio of concrete = 1 : 2 : 4
Now we find sum of this ratio (1 : 2 : 4)
= 1 + 2 + 4 = 7
1. First of all we find the quantity of cement by this formula.
Cement quantity = Cement ratio/Sum of ratio × Dry material
= 1 / 7 × 154 = 22 Cft
The volume of one bag cement is equal to 1.25
Then we find the bags to divide the volume of bag (1.25) from the found out the cement quantity (22).
= 22 ÷ 1.25 = 17.6 Say 18 bags.
2.In second step we will find the quantity of sand.
Sand quantity = Sand ratio / Sum of ratio × Dry material.
Sand quantity = 2 / 7 × 154 = Say 44 Cft sand.
3. In third step we will find the quantity of aggregates by this formula.
Quantity of aggregates = 4 / 7 × 154 = Say 88 Cft aggregates quantity.
Cost of material:
18 bags cement @Rs.690/bag = 18 × 690
= 12420.
44 Cft sand @Rs.200/50 = 44 × 200/50 = 176
88 Cft bajri @ Rs.300/50 = 88 × 300/50 = 52
Total cost of material = 12420 + 176 + 528 = 13124 amount
Note:44 Cft sand @Rs.200/50 = 44 × 200/50 = 176
88 Cft bajri @ Rs.300/50 = 88 × 300/50 = 52
Total cost of material = 12420 + 176 + 528 = 13124 amount
These are not exact rates of materials just for understanding.
Cost o f carriage :
18 bags cement @Rs.500/50 means (1 load =50 Cft ) = 18 × 500 / 50 = 180 say 200
44Cft sand @Rs.500/50 = 44 × 500 / 50 = 440 say 500
88 Cft bajri
@Rs.500/50 = 88 × 500 / 50 = 880 say 90
Total cost of carriage: 200 + 500 + 900 = 1600
Total cost of carriage: 200 + 500 + 900 = 1600
3 comments:
good info about rate analysis of concrete
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